Latest Maharashtra State Board (SSC & HSC) 2026-27 Syllabus Digest & Solutions Updated!
Class 8Mathematics & Statistics2026-27 Syllabus

Chapter 10 Division of Polynomials Practice Set 10.2 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 10 Division of Polynomials Practice Set 10.2. Step-by-step solved exercises, numerical problems, and digest answers.

381 words

Practice Set 10.2 8th Std Maths Answers Chapter 10 Division of Polynomials

Division of Polynomials Class 8 Practice Set 10.2 Question 1. Divide and write the quotient and the remainder.
i. (y2+ 10y + 24) ÷ (y + 4)
ii. (p2+ 7p – 5) ÷ (p + 3)
iii. (3x + 2x2+ 4x3) ÷ (x – 4)
iv. (2m3+ m2+ m + 9) ÷ (2m – 1)
v. (3x – 3x2– 12 + x4+ x3) ÷ (2 + x2)
vi. (a4– a3+ a2– a + 1) ÷ (a3– 2)
vii. (4x4– 5x3– 7x + 1) ÷ (4x – 1)
Solution:
i. (y2+ 10y + 24) ÷ (y + 4)

∴ Quotient = y + 6
Remainder = 0

ii. (p2+ 7p – 5) ÷ (p + 3)

∴ Quotient = p + 4
Remainder = -17

iii. (3x + 2x2+ 4x3) ÷ (x – 4)
Write the dividend in descending order of their indices.
3x + 2x² + 4x³ = 4x³ + 2x² + 3x

∴ Quotient = 4x² + 18x + 75
Remainder = 300

iv. (2m3+ m2+ m + 9) ÷ (2m – 1)

∴ Quotient = m² + m + 1
Remainder = 10

v. (3x – 3x2– 12 + x4+ x3) ÷ (2 + x2)
Write the dividend in descending order of their indices.
(x4+ x3– 3x2+ 3x – 12) ÷ (x2+ 2)

∴ Quotient = x² + x – 5
Remainder = x – 2

vi. (a4– a3+ a2– a + 1) ÷ (a3– 2)

∴ Quotient = a – 1
Remainder = a² + a – 1

vii. (4x4– 5x3– 7x + 1) ÷ (4x – 1)
Write the dividend in descending order of their indices.
(4x4– 5x3– 7x + 1) = (4x4– 5x3+ 0x2– 7x + 1)

∴ Quotient =
Remainder =