Latest Maharashtra State Board (SSC & HSC) 2026-27 Syllabus Digest & Solutions Updated!
Class 8Mathematics & Statistics2026-27 Syllabus

Chapter 10 Division of Polynomials Practice Set 10.1 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 10 Division of Polynomials Practice Set 10.1. Step-by-step solved exercises, numerical problems, and digest answers.

2 Solved Questions317 words

Practice Set 10.1 8th Std Maths Answers Chapter 10 Division of Polynomials

Question 1 Maharashtra Board Solution
Divide and write the quotient and the remainder. i. 21m² ÷ 7m ii. 40a³ ÷ (-10a) iii. (- 48p4) ÷ (- 9p2) iv. 40m5 ÷ 30m3 v. (5x3 – 3x2) ÷ x² vi. (8p3 – 4p2) ÷ 2p2 vii. (2y3 + 4y2 + 3 ) ÷ 2y2 viii. (21x4 – 14x2 + 7x) ÷ 7x3 ix. (6x5 – 4x4 + 8x3 + 2x2) ÷ 2x2 x. (25m4 – 15m3 + 10m + 8) ÷ 5m3
Solution & Step-by-Step Answer:
i. 21m² ÷ 7m ∴ Quotient = 3m Remainder = 0

ii. 40a³ ÷ (-10a)

∴ Quotient = -4a²
Remainder = 0

iii. (- 48p4) ÷ (- 9p2)

∴ Quotient = p²
Remainder = 0

iv. 40m5÷ 30m3

∴ Quotient = m²
Remainder = 0

v. (5x3– 3x2) ÷ x²

∴ Quotient = 5x – 3
Remainder = 0

vi. (8p3– 4p2) ÷ 2p2

∴ Quotient = 4p – 2
Remainder = 0

vii. (2y3+ 4y2+ 3 ) ÷ 2y2

∴ Quotient = y + 2
Remainder = 3

viii. (21x4– 14x2+ 7x) ÷ 7x3

∴ Quotient = 3x
Remainder = -14x² + 7x

ix. (6x5– 4x4+ 8x3+ 2x2) ÷ 2x2

∴ Quotient = 3x³ – 2x² + 4x + 1
Remainder = 0

x. (25m4– 15m3+ 10m + 8) ÷ 5m3

∴ Quotient = 5m – 3
Remainder = 10m + 8

Maharashtra Board Class 8 Maths Chapter 10 Division of Polynomials Practice Set 10.1 Intext Questions and Activities

Question 1 Maharashtra Board Solution
Fill in the blanks in the following examples. (Textbook pg. no. 61)

Solution & Step-by-Step Answer: