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Class 9 (SSC)Mathematics & Statistics2026-27 Syllabus

Chapter 9 Surface Area and Volume Practice Set 9.1 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 9 Surface Area and Volume Practice Set 9.1. Step-by-step solved exercises, numerical problems, and digest answers.

8 Solved Questions903 words

Practice Set 9.1 Geometry 9th Std Maths Part 2 Answers Chapter 9 Surface Area and Volume

Question 1 Maharashtra Board Solution
Length, breadth and height of a cuboid shape box of medicine is 20 cm, 12 cm and 10 cm respectively. Find the surface area of vertical faces and total surface area of this box. Given: For cuboid shape box of medicine, length (l) = 20 cm, breadth (b) = 12 cm and height (h) = 10 cm. To find: Surface area of vertical faces and total surface area of the box
Solution & Step-by-Step Answer:
i. Surface area of vertical faces of the box = 2(l + b) x h = 2(20+ 12) x 10 = 2 x 32 x 10 = 640 sq.cm.

ii. Total surface area of the box
= 2 (lb + bh + lh)
= 2(20 x 12+ 12 x 10 + 20 x 10)
= 2(240 + 120 + 200)
= 2 x 560
= 1120 sq.cm.
∴ The surface area of vertical faces and total surface area of the box are 640 sq.cm, and 1120 sq.cm, respectively.

Question 2 Maharashtra Board Solution
Total surface area of a box of cuboid shape is 500 sq.unit. Its breadth and height is 6 unit and 5 unit respectively. What is the length of that box? Given: For cuboid shape box, breadth (b) = 6 unit, height (h) = 5 unit Total surface area = 500 sq. unit. To find: Length of the box (l)
Solution & Step-by-Step Answer:
Total surface area of the box = 2 (lb + bh + lh) ∴ 500 = 2 (6l + 6 x 5 + 5l) ∴ = (11l + 30) ∴ 250= 11l + 30 ∴ 250 – 30= 11l ∴ 220 = 11l ∴ 220 = l ∴ = l ∴ l = 20 units ∴ The length of the box is 20 units.
Question 3 Maharashtra Board Solution
Side of a cube is 4.5 cm. Find the surface area of all vertical faces and total surface area of the cube. Given: Side of cube (l) = 4.5 cm To find: Surface area of all vertical faces and the total surface area of the cube
Solution & Step-by-Step Answer:
i. Area of vertical faces of cube = 4l2 = 4 (4.5)2 = 4 x 20.25 = 81 sq.cm. ii. Total surface area of the cube = 6l2 = 6 (4.5)2 = 6 x 20.25 = 121.5 sq.cm. ∴ The surface area of all vertical faces and the total surface area of the cube are 81 sq.cm, and 121.5 sq.cm, respectively.
Question 4 Maharashtra Board Solution
Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube. Given: Total surface area of cube = 5400 sq.cm. To find: Surface area of all vertical faces of the cube
Solution & Step-by-Step Answer:
i. Total surface area of cube = 6l2 ∴ 5400 = 6l2 ∴ = l2 ∴ l2 = 900 ii. Area of vertical faces of cube = 4l2 = 4 x 900 = 3600 sq.cm. ∴ The surface area of all vertical faces of the cube is 3600 sq.cm.
Question 5 Maharashtra Board Solution
Volume of a cuboid is 34.50 cubic metre. Breadth and height of the cuboid is 1.5 m and 1.15 m respectively. Find its length. Given: Breadth (b) = 1.5 m, height (h) = 1.15 m Volume of cuboid = 34.50 cubic metre To find: Length of the cuboid (l)
Solution & Step-by-Step Answer:
Volume of cuboid = l x b x h ∴ 34.50 = l x b x h ∴ 34.50 = l x 1.5 x 1.15 = 20 ∴ The length of the cuboid is 20 m.
Question 6 Maharashtra Board Solution
What will be the volume of a cube having length of edge 7.5 cm ? Given: Length of edge of cube (l) = 7.5 cm To find: Volume of a cube
Solution & Step-by-Step Answer:
Volume of a cube = l2 = (7.5)3 = 421.875 ≈ 421.88 cubic cm ∴The volume of the cube is 421.88 cubic cm.
Question 7 Maharashtra Board Solution
Radius of base of a cylinder is 20 cm and its height is 13 cm, find its curved surface area and total surface area, (π = 3.14) Given: Radius (r) = 20 cm, height (h) = 13 cm To find: Curved surface area and the total surface area of the cylinder
Solution & Step-by-Step Answer:
i. Curved surface area of cylinder = 2πrh = 2 x 3.14 x 20 x 13 = 1632.8 sq.cm

ii. Total surface area of cylinder = 2πr(r + h)
= 2 x 3.14 x 20(20 + 13)
= 2 x 3.14 x 20 x 33 = 4144.8 sq.cm
∴ The curved surface area and the total surface area of the cylinder are 1632.8 sq.cm and 4144.8 sq.cm respectively.

Question 8 Maharashtra Board Solution
Curved surface area of a cylinder is 1980 cm2 and radius of its base is 15 cm. Find the height of the cylinder. (π = ) Given: Curved surface area of cylinder = 1980 sq.cm., radius (r) = 15 cm To find: Height of the cylinder (h)
Solution & Step-by-Step Answer:
Curved surface area of cylinder = 2πrh ∴ 1980 = 2 x x 15 x h ∴ ∴ h = 21 cm ∴ The height of the cylinder is 21 cm.