Practice Set 3.1 Algebra 9th Std Maths Part 1 Answers Chapter 3 Polynomials
Solution & Step-by-Step Answer:
i. No, because power of v in the term 5√x is -1 (negative number). ii. No, because the power of x in the term 5√x is i. e. 0.5 (decimal number). iii. Yes. All the coefficients are real numbers. Also, the power of each term is a whole number. iv. No, because the power of m in the term 2m-2 is -2 (negative number). v. Yes, because 10 is a constant polynomial.
Solution & Step-by-Step Answer:
i. 1 ii. -√3 iii. –
Solution & Step-by-Step Answer:
i. 5x7 ii. x35 – 1 iii. 3x8 + 2x6 + x5
Solution & Step-by-Step Answer:
i. √5 = √5 x° ∴ Degree of the polynomial = 0
ii. x°
∴Degree of the polynomial = 0
iii. x2
∴Degree of the polynomial = 2
iv. √2m10– 7
Here, the highest power of m is 10.
∴Degree of the polynomial = 10
v. 2p – √7
Here, the highest power of p is 1.
∴ Degree of the polynomial = 1
vi. 7y – y3+ y5
Here, the highest power of y is 5.
∴Degree of the polynomial = 5
vii. xyz + xy – z
Here, the sum of the powers of x, y and z in the term xyz is 1 + 1 + 1= 3,
which is the highest sum of powers in the given polynomial.
∴Degree of the polynomial = 3
viii. m3n7– 3m5n + mn
Here, the sum of the powers of m and n in the term m3n7is 3 + 7 = 10,
which is the highest sum of powers in the given polynomial.
∴ Degree of the polynomial = 10
Solution & Step-by-Step Answer:
Linear polynomials: ii, iii Quadratic polynomials: i, v Cubic polynomials: iv, vi
Solution & Step-by-Step Answer:
i. m3 + 5m + 3 ii. y5 + 2y4 + 3y3 – y2 – 7y –
Solution & Step-by-Step Answer:
i. x3 – 2 = x3 + 0x2 + 0x – 2 ∴ Coefficient form of the given polynomial = (1, 0, 0, -2)
ii. 5y = 5y + 0
∴Coefficient form of the given polynomial = (5,0)
iii. 2m4– 3m2+ 7
= 2m4+ Om3– 3m2+ 0m + 7
∴ Coefficient form of the given polynomial = (2, 0, -3, 0, 7)
iv. –
∴Coefficient form of the given polynomial = (- )
Solution & Step-by-Step Answer:
i. Number of coefficients = 3 ∴ Degree = 3 – 1 = 2 ∴ Taking x as variable, the index form is x2 + 2x + 3
ii. Number of coefficients = 5
∴ Degree = 5 – 1=4
∴ Taking x as variable, the index form is 5x4+ 0x3+ 0x2+ 0x – 1
iii. Number of coefficients = 4
∴Degree = 4 – 1 = 3
∴Taking x as variable, the index form is -2x3+ 2x2– 2x + 2
Solution & Step-by-Step Answer:
i. Quadratic polynomial: x2; 2x2 + 5x + 10; 3x2 + 5x ii. Cubic polynomial: x3 + x2 + x + 5; x3 + 9 iii. Linear polynomial: x + 7 iv. Binomial: x + 7; x3 + 9; 3x2 + 5x v. Trinomial: 2x2 + 5x + 10 vi. Monomial: x2
Solution & Step-by-Step Answer:
Monomial: x5 Binomial: x5 + x Trinomial: 2x5 – x2 + 5
Solution & Step-by-Step Answer:
x3y2 + xy