Practice Set 2.1 Algebra 9th Std Maths Part 1 Answers Chapter 2 Real Numbers
ii. Denominator = 11 = 1 x 11
Since, the denominator is other than prime factors 2 or 5.
∴ the decimal form of the rational number will be non-terminating recurring type.
iii. Denominator = 16
= 2 x 2 x 2 x 2
Since, 2 is the only prime factor in the denominator.
∴ the decimal form of the rational number will be terminating type.
iv. Denominator = 125
= 5 x 5 x 5
Since, 5 is the only prime factor in the denominator.
the decimal form of the rational number will be terminating type.
v. Denominator = 6
= 2 x 3
Since, the denominator is other than prime factors 2 or 5.
∴ the decimal form of the rational number will be non-terminating recurring type.
ii.
iii. √5
iv.
v.
ii. Let x =
∴ x = 0.3737…
Since, two numbers i.e. 3 and 7 are repeating after the decimal point.
Thus, multiplying both sides by 100,
100x = 37.3737……
∴ 100x = ……(ii)
Subtracting (i) from (ii),
100x – x = –
∴ 99x = 37
iii. Letx = …(i)
∴ x = 3.1717…
Since, two numbers i.e. 1 and 7 are repeating after the decimal point.
Thus, multiplying both sides by 100,
100x = 317.1717…
∴ 100x= 317.17 …(ii)
Subtracting (i) from (ii),
100x – x = –
∴ 99x = 314
iv. Let x = …….. (i)
∴ x = 15.8989…
Since, two numbers i.e. 8 and 9 are repeating after the decimal point.
Thus, multiplying both sides by 100,
100x= 1589.8989…
∴ 100x = …(ii)
Subtracting (i) from (ii),
100x – x = –
∴ 99x = 1574
v. Let x =
∴ x = 2.514514…
Since, three numbers i.e. 5, 1 and 4 are repeating after the decimal point.
Thus, multiplying both sides by 1000,
1000x = 2514.514514…
1000x = ….(ii)
Subtracting (i) from (ii),
1000x – x = –
∴ 999x = 2512