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Class 7Science & Technology2026-27 Syllabus

Chapter 7 Motion, Force and Work Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 7 Motion, Force and Work. Step-by-step solved exercises, numerical problems, and digest answers.

30 Solved Questions11 Diagrams2035 words

Maharashtra State Board Class 7 Science Solutions Chapter 7 Motion, Force and Work

Class 7 Science Chapter 7 Motion, Force and Work Textbook Questions and Answers

1. Fill ¡n the blanks with the proper words from the brackets.
(stationary, zero, changing, constant, displacement, velocity, speed. acceleration, stationary but not zero. inc reuses)

Question a.
If a body traverses a distance in direct proportion to the time, the speed of the body is ……………….
Answer:
constant

Question b.
If a body is moving with a constant velocity, its acceleration is ……………….
Answer:
zero

Question c.
……………. is a scalar quantity.
Answer:
Speed

Question d.
…………….. is the distance traversed by a body in a particular direction in unit time.
Answer:
Velocity

2. Observe the figure and answer the questions.

Sachin and Sarneer started on a motorbike from place A, took the turn at 13, did a task at C, travelled by the route CD to D and then went on to E. Altogether, they took one hour for this journey. Find out the actual distance traversed by them and the displacement from A to E. From this, deduce their speed. What was their velocity from A to E in the direction AE’? Can this velocity be called average velocity?

Question a.
Observe the figure and answer the questions

Sachin and Sarneer started on a motorbike from place A, took the turn at 13, did a task at C, travelled by the route CD to D and then went on to E. Altogether, they took one hour for this journey. Find out the actual distance traversed by them and the displacement from A to E. From this, deduce their speed. What was their velocity from A to E in the direction AE’? Can this velocity be called average velocity?
Answer:
1. Actual distance = + + + = 3 + 4 + 5 + 3
Actual distance = 15 km

2. Displacement = + +
= 3 + 3 + 3
Displacement = 9 km

3. Speed =
Distance = 15 km = 15 × 1000 = 15000 m
Time = 1 hr = 1 × 60 × 60 = 3600 sec.
s = or s = = 15km/hour
= 4.16 m/sec. or 15 km/hour

4. Velocity =
Displacement = 9 km = 9 × 1000 = 9000 m
Time = 1 hr = 1 × 60 × 60 = 3600 sec
V = or V = = 9 km/hour
= 2.5 m/sec. or 9 km/hour

5. Yes, this velocity can be called as average velocity.

3. From the groups B and C, choose the proper words, for each of the words in group A.

Question a.
From the groups B and C, choose the proper words, for each of the words in group A.

Answer:

Group ‘A’

Group B’

Group ‘C’

Work

Joule

erg

Force

Newton

dyne

Displacement

Metre

cm

4. A bird sitting on a wire, flies, circles around and comes back to its perch. Explain the total distance it traversed during its flight and its eventual displacement.

Question a.
Answer:
The total distance the bird has traversed is the length of the distance covered by circling, but the eventual displacement are the bird is zero as its initial and final position are one and the same.

5. Explain the following concepts in your own words with everyday examples: force, work, displacement, velocity, acceleration, distance.

Question a.
Explain the following concepts in your own words with everyday examples: force, work, displacement, velocity, acceleration, distance.
Answer:
1. Force: The interaction that brings about the acceleration is called force.
e.g: An ox is pulling a cart, applying brakes to a bicycle, lifting heavy iron object with a crane.

2. Work: When an object is displaced by applying a force on it, work is said to be done.
e.g: A bucketful of water is to be drawn from a well and taken to the home by walking from well to home.

3. Displacement: The minimum distance
traversed by a moving body in one direction from the original point to reach the final point is called displacement.
e.g: A rolling of a ball from point A to point B in the same direction.

4. Velocity: Velocity is the distance traversed by a body in a specific direction in unit time.
e.g: A truck is covering a distance of 40km from A to D in a straight line in 1 hour.

5. Acceleration: It is change in velocity per second. It can be deduced.
Acceleration =
e.g:

(i) In the above example a truck covered the distance AB at velocity of 60 km/hr, BC at 30 km/hr and CD at 40 km/hr. (ii) It means that the velocity for the distance CD is greater than the velocity for the distance BC. (iii) From the number of seconds required for this change in velocity to take place, the change in velocity per second can be deduced. This is called acceleration (iv) Distance: The length of the route actually traversed by a moving body irrespective of the direction is called distance.
e.g: Ranjit travelled 1km. from his home to school.

6. A ball is rolling from A to D on a flat and smooth surface. Its speed is 2 cm/s. On reaching B, it was pushed continuously up to C. On reaching D from C, its speed had become 4 cm/s. It took 2 seconds for it to go from B to C. What is the acceleration of the ball as it goes from B to C.

Question a.
A ball is rolling from A to D on a flat and smooth surface. Its speed is 2 cm/s. On reaching B, it was pushed continuously up to C. On reaching D from C, its speed had become 4 cm/s. It took 2 seconds for it to go from B to C. What is the acceleration of the ball as it goes from B to C.

Answer:
As its initial and final positions are one and the same.
Initial Velocity = 2 cm/s.
Final Velocity = 4 cm/s
Time taken for the change in velocity from B to
D = 4 cm/s – 2 cm/s = 2 cm/s

7. Solve the following problems.

Question a.
A force of 1000 N was applied to stop a car that was moving with a constant velocity. The car stopped after moving through 10m. How much is the work done?
Answer:
Force (F) = 1000 N
displacement (s) = 10m
work done (W) = ?
W = Fs
= 1000 × 10
W = 10,000 Joule

Question b.
A cart with mass 20 kg went 50 m in a straight line on a plain and smooth road when a force of 2 N was applied to it. How much work was done by the force?
Answer:
Force (F) = 2 N
Displacement (s) = 50 m
Work done (W) = ?
W = Fs
= 2 × 50
W = 100 Joule

Project:

Question a.
Collect information about the study made by Sir Isaac Newton regarding force and acceleration and discuss it with your teacher.

Class 7 Science Chapter 7 Motion, Force and Work Important Questions and Answers

Fill in blanks:

Question 1 Maharashtra Board Solution
Displacement is a …………. quantity.
Solution & Step-by-Step Answer:
vector
Question 2 Maharashtra Board Solution
The …………. of an object can change even while it is moving along a straight line.
Solution & Step-by-Step Answer:
velocity
Question 3 Maharashtra Board Solution
The …………. velocity can be different at different times.
Solution & Step-by-Step Answer:
instantaneous
Question 4 Maharashtra Board Solution
Change in velocity per second is called …………..
Solution & Step-by-Step Answer:
acceleration
Question 5 Maharashtra Board Solution
The interaction that brings about the acceleration is called …………..
Solution & Step-by-Step Answer:
force
Question 6 Maharashtra Board Solution
The scientist …………. was the first to study force and the resulting acceleration.
Solution & Step-by-Step Answer:
Sir Isaac Nezvton
Question 7 Maharashtra Board Solution
Ability to do work is called …………..
Solution & Step-by-Step Answer:
Energy
Question 8 Maharashtra Board Solution
W = …………. × S.
Solution & Step-by-Step Answer:
F
Question 9 Maharashtra Board Solution
Unit of work is …………. and …………..
Solution & Step-by-Step Answer:
Joule, erg
Question 10 Maharashtra Board Solution
Unit of force is …………. and …………..
Solution & Step-by-Step Answer:
Newton, dyne
Question 11 Maharashtra Board Solution
Force is a …………. quantity.
Solution & Step-by-Step Answer:
vector
Question 12 Maharashtra Board Solution
The velocity at a particular time is called …………. velocity.
Solution & Step-by-Step Answer:
instantaneous
Question 13 Maharashtra Board Solution
The …………. of a body is the distance traversed per unit time.
Solution & Step-by-Step Answer:
speed
Question 14 Maharashtra Board Solution
Unit of acceleration is …………. and …………..
Solution & Step-by-Step Answer:
m/s2 and cm/s2
Question 15 Maharashtra Board Solution
Force is measured by the …………. that it produces.
Solution & Step-by-Step Answer:
acceleration
Question 16 Maharashtra Board Solution
Work done by a body with no displacement will be …………..
Solution & Step-by-Step Answer:
zero

Say whether True or False, correct the false 1 statements:

Question 1 Maharashtra Board Solution
Velocity is distance travelled per unit of time.
Solution & Step-by-Step Answer:
False. Speed is distance travelled per unit of time
Question 2 Maharashtra Board Solution
In displacement, both distance and direction are taken into account.
Solution & Step-by-Step Answer:
True
Question 3 Maharashtra Board Solution
Speed = Distance/time.
Solution & Step-by-Step Answer:
True
Question 4 Maharashtra Board Solution
Change in speed per second is acceleration.
Solution & Step-by-Step Answer:
False. Change in velocity per second is acceleration
Question 5 Maharashtra Board Solution
Work done depends on the force and the displacement.
Solution & Step-by-Step Answer:
True
Question 6 Maharashtra Board Solution
C.G.S. unit of acceleration is m/s2.
Solution & Step-by-Step Answer:
False. C.G.S. unit of acceleration is cm/s2.
Question 7 Maharashtra Board Solution
M.K.S. unit of force is dyne.
Solution & Step-by-Step Answer:
False. M.K.S. unit of force is Newton
Question 8 Maharashtra Board Solution
Force is measured by the acceleration that it produces.
Solution & Step-by-Step Answer:
True

Write the difference between the following:

Question 1 Maharashtra Board Solution
Speed and Velocity
Solution & Step-by-Step Answer:

Speed

Velocity

1. Speed is distance travelled per unit of time.

1. Velocity is the distance traversed by a body in a specific direction in unit time.

2. It is a scalar quantity.

2. It is a vector quantity.

3. Formula:
Speed =

3. Formula:
Velocity =

Question 2 Maharashtra Board Solution
Distance and Displacement
Solution & Step-by-Step Answer:

Distance

Displacement

1. The length of the route actually traversed by a moving body, irrespective of the direction is called distance.

1. The minimum distance traversed by a moving body in one direction from the original point to reach the final point is called displacement.

2. It is a scalar quantity.

2. It is a vector quantity.

Solve the following problems!

Question 1 Maharashtra Board Solution
A bus travelled 200 km in the first 3 hours and then 100 kms for the next one and a half hours and then 120 kms for the next one and a half hours. What is the average velocity of the bus if it has moved in a straight line for the whole journey.
Solution & Step-by-Step Answer:

Question 2 Maharashtra Board Solution
See the diagram and calculate the Distance and Displacement travelled by the body from A to I.
Solution & Step-by-Step Answer:
Distance travelled = A → B → C → D → E → F → G → H + I = 5 + 7 + 6 + 3 + 5 + 4 + 6 + 5 = 41 m Displacement = A → I in a straight line shortest distance = 1m

Use your brainpower:

Question 1 Maharashtra Board Solution
The unit of acceleration is m/s2, verify this.
Solution & Step-by-Step Answer:

Question 2 Maharashtra Board Solution
Acceleration is a vector quantity. Is force a vector quantity too?
Solution & Step-by-Step Answer:
Yes, acceleration and force both are vector quantities, because both can be expressed completely only when magnitude and direction are given and the quantity which needs direction and magnitude both is called a vector quantity.