Algebraic Expressions and Operations on them Class 7 Practice Set 34 Answers Solutions Chapter 8
Question 1
Maharashtra Board Solution
Subtract the second expression from the first. i. (4xy – 9z); (3xy – 16z) ii. (5x + 4y + 7z); (x + 2y + 3z) iii. (14x² + 8xy + 3y²); (26x² – 8xy – 17y²) iv. (6x² + 7xy + 16y²); (16x² – 17xy) v. (4x + 16z); (19y – 14z + 16x)
Solution & Step-by-Step Answer:
i. (4xy – 9z) – (3xy – 16z) = 4xy – 9z – 3xy + 16z = (4xy – 3xy) + (16z – 9z) = xy + 7z
ii. (5x + 4y + 7z) – (x + 2y + 3z)
= 5x + 4y + 7z – x – 2y – 3z
= (5x – x) + (4y – 2y) + (7z – 3z)
= 4x + 2y + 4z
iii. (14x² + 8xy + 3y²) – (26x² – 8xy – 17y²)
= 14x² + 8xy + 3y² – 26x² + 8xy + 17y²
= (14x² – 26x²) + (8xy + 8xy) + (3y² + 17y²)
= -12x² + 16xy + 20y²
iv. (6x² + 7xy + 16y²) – (16x² – 17xy)
= 6x² + 7xy + 16y² – 16x² + 17xy
= (6x² – 16x²) + (7xy + 17xy) + 16y²
= -10x² + 24xy + 16y²
v. (4x + 16z) – (19y— 14z + 16x)
= 4x + 16z – 19y + 14z – 16x
= (4x – 16x) – 19y + (16z + 14z)
= -12x – 19y + 30z