6th Standard Maths Practice Set 14 Answers Chapter 5 Decimal Fractions
Question 1
Maharashtra Board Solution
In the table below, write the place value of each of the digits in the number 378.025.
Place | Hundreds | Tens | Units | Tenths | Hundredths | Thousandths |
100 | 10 | 1 | ||||
Digit | 3 | 7 | 8 | 0 | 2 | 5 |
Place value | 300 |
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Solution & Step-by-Step Answer:
Place | Hundreds | Tens | Units | Tenths | Hundredths | Thousandths |
100 | 10 | 1 | ||||
Digit | 3 | 7 | 8 | 0 | 2 | 5 |
Place value | 300 | 7 × 10 = 70 | 8 × 1 = 8 |
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Question 2
Maharashtra Board Solution
Solve : i. 905.5 + 27.197 ii. 39 + 700.65 iii. 40 + 27.7 + 2.451
Solution & Step-by-Step Answer:
i. 905.5 + 27.197
ii. 39 + 700.65 iii. 40 + 27.7 + 2.451
Question 3
Maharashtra Board Solution
Subtract: i. 85.96 – 2.345 ii. 632.24 – 97.45 iii. 200.005 – 17.186
Solution & Step-by-Step Answer:
i. 85.96 – 2.345
ii. 632.24 – 97.45 iii. 200.005 – 17.186
Question 4
Maharashtra Board Solution
Avinash traveled 42 km 365 m by bus, 12 km 460 in by car and walked 640 m. How many kilometers did he travel altogether? (Write your answer in decimal fractions)
Solution & Step-by-Step Answer:
Distance traveled in bus = 42 km 365 m = 42 km + km = 42 km + 0.365 km = 42.365 km Distance travelled in car = 12 km 460 m = 12 km + km = 12 km + 0.460 km = 12.460 km Distance walked = 640 m = = 0.640 km ∴ Total distance travelled = Distance travelled in bus + Distance travelled in car + Distance walked = 42.365 + 12.460 + 0.640 = 55.465 km ∴ Distance travelled altogether by Avinash is 55.465 km.
Question 5
Maharashtra Board Solution
Ayesha bought 1.80 m of cloth for her salwaar and 2.25 for her kurta. If the cloth costs Rs 120 per metre, how much must she pay the shopkeeper?
Solution & Step-by-Step Answer:
Total length of cloth bought = 1.80 m + 2.25 m = 4.05 m Cost of 1 m of cloth = Rs 120 ∴ Cost of 4.05 m of cloth = 4.05 x 120 ∴ Amount to be paid to the shopkeeper is Rs 486.
Question 6
Maharashtra Board Solution
Sujata bought a watermelon weighing 4.25 kg and gave 1 kg 750 g to the children in her neighbourhood. How much of it does she have left?
Solution & Step-by-Step Answer:
Total weight of watermelon = 4.25 kg Weight of watermelon given to children = 1 kg 750 g = 1 kg + kg = 1 kg + 0.75 kg = 1.75 kg ∴ Weight of watermelon left = Total weight of watermelon – Weight of watermelon given to children = 4.25 kg – 1.75 kg = 2.5 kg ∴ Weight of watermelon left with Sujata is 2.5 kg.
Question 7
Maharashtra Board Solution
Anita was driving at a speed of 85.6 km per hour. The road had a speed limit of 55 km per hour. By how much should she reduce her speed to be within the speed limit?
Solution & Step-by-Step Answer:
Speed at which Anita is driving = 85.6 km per hr. Speed limit = 55 km per hr. ∴ Anita should reduce her speed by 85.6 km per hr – 55 km per hr. = 30.6 km per hr. ∴ Anita should reduce her speed by 30.6 km per hour to be within the speed limit.
Maharashtra Board Class 6 Maths Chapter 4 Operations on Fractions Practice Set 14 Intext Questions and Activities
Question 1
Maharashtra Board Solution
Nandu went to a shop to buy a pen, notebook, eraser and a paint box. The shopkeeper told him the prices. A pen costs four and a half rupees, an eraser one and a half, a notebook six and a half and a paintbox twenty-five rupees and fifty paise. Nandu bought one of each article. Prepare his bill. If Nandu gave a 100 rupee note, how much money does he get back? (Textbook pg. no. 29) Nandu will get __ rupees back.
Solution & Step-by-Step Answer:
100 – 38 = 62.00 Nandu will get Rs 62 rupees back.
Question 2
Maharashtra Board Solution
Take a pen and notebook with you when you go to the market with your parent. Note the weight of every vegetable your mother buys. Find out the total weight of those vegetables. (Textbook pg. no. 30)
Solution & Step-by-Step Answer:
(Students should attempt this activity on their own.)
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