Latest Maharashtra State Board (SSC & HSC) 2026-27 Syllabus Digest & Solutions Updated!
Class 5Mathematics & Statistics2026-27 Syllabus

Chapter 5 Fractions Problem Set 22 Solutions

Complete Maharashtra State Board Balbharati & Yuvakbharati textbook solutions for Chapter 5 Fractions Problem Set 22. Step-by-step solved exercises, numerical problems, and digest answers.

2 Solved Questions20 Diagrams391 words

BalbhartiMaharashtra Board Class 5 Maths SolutionsChapter 5 Fractions Problem Set 22 Textbook Exercise Important Questions and Answers.

Maharashtra State Board Class 5 Maths Solutions Chapter 5 Fractions Problem Set 22

Question 1 Maharashtra Board Solution
Add the following:


Solution & Step-by-Step Answer:

The smallest common multiple of 4 and 8 is 8. So making 8 is the common denominator of the given fractions.

Answer:


Solution:
21 is the multiple of 7. So making 21 as denominator of both the fractions.

Answer:


Solution:
Least common multiple of 5 and 3 is 15. So making common denominator of both the fractions 15.

Answer:


Solution:
Smallest common multiple of 2 and 7 is 14. So, making denominator of both the fractions 14.

Answer:


Solution:
Smallest common multiple of 9 and 5 is 45.

Answer:

Question 2 Maharashtra Board Solution
Subtract the following:

Solution & Step-by-Step Answer:
20 is the multiples of 10. So,


Answer:


Solution:
4 is the multiple of 2. So,

Answer:


Solution:
14 is the multiples of 7. So,

Answer:


Solution:
Smallest common multiple of 6 and 5 is 30. So,

Answer:


Solution:
Smallest common multiple of 7 and 4 is 28.

Answer:

A fraction of a collection and a multiple of a fraction

of a collection of 20 dots – of a collection of 20 dots

of a collection of 20 dots

Twice 5 is 10 – times 10

Thrice 5 – times 15

times 15

Meena has 5 rupees. Tina has twice as many rupees. That is, Tina has 5 × 2 = 10 rupees. Meena has half as many rupees as Tina, that is, of 10, or, 5 rupees.

Ramu has to travel a distance of 20 km. If he has travelled of the distance by car, how many kilometres did he travel by car?
of 20 km is 20 × . So, we take of 20, 4 times.
of 20 = 4. 4 times 4 is 4 × 4 = 16.
It means that 20 × = 16.
Ramu travelled a distance of 16 kilometres by car.

Addition and Subtraction Problem Set 13 Additional Important Questions and Answers


Solution:
12 is the multiple of 6

Answer:


Solution:
Here 9 is the multiples of 3. So, making like fractions of denominator 9, we get

Answer:

Subtract the following:


Solution:
Common multiple of 9 and 5 is 45

Answer:


Answer: