Balbharati Maharashtra State Board12th Commerce Maths Solution Book PdfChapter 3 Differentiation Miscellaneous Exercise 3 Questions and Answers.
Maharashtra State Board 12th Commerce Maths Solutions Chapter 3 Differentiation Miscellaneous Exercise 3
(I) Choose the correct alternative:
Question 1
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If y = (5x3 – 4x2 – 8x)9, then = ___________ (a) 9(5x3 – 4x2 – 8x)8 (15x2 – 8x – 8) (b) 9(5x3 – 4x2 – 8x)9 (15x2 – 8x – 8) (c) 9(5x3 – 4x2 – 8x)8 (5x2 – 8x – 8) (d) 9(5x3 – 4x2 – 8x)9 (5x2 – 8x – 8)
Solution & Step-by-Step Answer:
(a) 9(5x3 – 4x2 – 8x)8 (15x2 – 8x – 8)
Question 2
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If y = , then = ? (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(c) Hint:

Question 3
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If y = then = ? (a) (b) (c) 0 (d)
Solution & Step-by-Step Answer:
(a)
Question 4
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If y = 2x2 + 22 + a2, then = ? (a) x (b) 4x (c) 2x (d) -2x
Solution & Step-by-Step Answer:
(b) 4x
Question 5
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If y = 5x. x5, then = ? (a) 5x. x4(5 + log 5) (b) 5x. x5(5 + log 5) (c) 5x. x4(5 + x log 5) (d) 5x. x5(5 + x log 5)
Solution & Step-by-Step Answer:
(c) 5x. x4(5 + x log 5)
Question 6
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If y = then = ? (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(b) Hint:

Question 7
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If ax2 + 2hxy + by2 = 0, then = ? (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(b)
Question 8
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If x4. y5 = (x + y)(m+1) and then m = ? (a) 8 (b) 4 (c) 5 (d) 20
Solution & Step-by-Step Answer:
(a) 8 Hint: If xp. yq = (x + y)p+q, then ∴ m + 1 = 4 + 5 = 9 ∴ m = 8.
Question 9
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If x = , y = then = ? (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(d) Hint:

Question 10
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If x = 2at2, y = 4at, then = ? (a) (b) (c) (d)
Solution & Step-by-Step Answer:
(c)
(II) Fill in the blanks:
Question 1
Maharashtra Board Solution
If 3x2y + 3xy2 = 0 then = …………
Solution & Step-by-Step Answer:
-1 Hint: 3x2y + 3xy2 = 0 ∴ 3xy(x + y) = 0 ∴ x + y = 0 ∴ y = -x ∴ = -1
Question 2
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If xm. yn = (x+y)(m+n) then
Solution & Step-by-Step Answer:
y
Question 3
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If 0 = log(xy) + a then
Solution & Step-by-Step Answer:
x
Question 4
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If x = t log t and y = tt then = …………
Solution & Step-by-Step Answer:
y Hint: x = t log t = log tt = log y ∴ 1 = ∴ = y
Question 5
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If y = x. log x then = …………..
Solution & Step-by-Step Answer:
Question 6
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If y = [log(x)]2 then = …………..
Solution & Step-by-Step Answer:
Hint:

Question 7
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If x = y + then = …………
Solution & Step-by-Step Answer:
Hint:

Question 8
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If y = eax, then x. = …………
Solution & Step-by-Step Answer:
axy
Question 9
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If x = t. log t, y = tt then = …………
Solution & Step-by-Step Answer:
y
Question 10
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If y = then = ………
Solution & Step-by-Step Answer:
my Hint:

(III) State whether each of the following is True or False:
Question 1
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If f’ is the derivative of f, then the derivative of the inverse of f is the inverse of f’.
Solution & Step-by-Step Answer:
False
Question 2
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The derivative of loga x, where a is constant is .
Solution & Step-by-Step Answer:
True
Question 3
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The derivative of f(x) = ax, where a is constant is x. ax-1
Solution & Step-by-Step Answer:
False
Question 4
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The derivative of a polynomial is polynomial.
Solution & Step-by-Step Answer:
True
Question 5
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Solution & Step-by-Step Answer:
False
Question 6
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If y = log x, then .
Solution & Step-by-Step Answer:
True
Question 7
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If y = e2, then = 2e.
Solution & Step-by-Step Answer:
False
Question 8
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The derivative of ax is ax. log a.
Solution & Step-by-Step Answer:
True
Question 9
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The derivative of xm. yn = (x + y)(m+n) is
Solution & Step-by-Step Answer:
False
(IV) Solve the following:
Question 1
Maharashtra Board Solution
If y = (6x3 – 3x2 – 9x)10, find
Solution & Step-by-Step Answer:
Given y = (6x3 – 3x2 – 9x)10

Question 2
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If y = , find .
Solution & Step-by-Step Answer:

Question 3
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If y = [log(log(log x))]2, find .
Solution & Step-by-Step Answer:


Question 4
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Find the rate of change of demand (x) of a commodity with respect to its price (y) if y = 25 + 30x – x2.
Solution & Step-by-Step Answer:

Question 5
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Find the rate of change of demand (x) of a commodity with respect to its price (y) if y =
Solution & Step-by-Step Answer:

Question 6
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Find if y = xx.
Solution & Step-by-Step Answer:
y = xx ∴ log y = log xx = x log x Differentiating both sides w.r.t. x, we get

Question 7
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Find if y = .
Solution & Step-by-Step Answer:

Question 8
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Find , if y =
Solution & Step-by-Step Answer:


Question 9
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Find if y = xx + (7x – 1)x
Solution & Step-by-Step Answer:


Question 10
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If y = x3 + 3xy2 + 3x2y, find .
Solution & Step-by-Step Answer:
y = x3 + 3xy2 + 3x2y Differentiating both sides w.r.t. x, we get

Question 11
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If x3 + y2 + xy = 7, find .
Solution & Step-by-Step Answer:
x3 + y2 + xy = 7 Differentiating both sides w.r.t. x, we get

Question 12
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If x3y3 = x2 – y2, find .
Solution & Step-by-Step Answer:
x3y3 = x2 – y2 Differentiating both sides w.r.t. x, we get

Question 13
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If x7. y9 = (x + y)16, then show that .
Solution & Step-by-Step Answer:


Question 14
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If xa. yb = (x + y)a+b, then show that .
Solution & Step-by-Step Answer:

Question 15
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Find if x = 5t2, y = 10t.
Solution & Step-by-Step Answer:
x = 5t2, y = 10t Differentiating x and y w.r.t. t, we get

Question 16
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Find if x = e3t, y = .
Solution & Step-by-Step Answer:
x = e3t, y = Differentiating x and y w.r.t. t, we get

Question 17
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Differentiate log(1 + x2) with respect to ax.
Solution & Step-by-Step Answer:
Let u = log(1 + x2) and v = ax Then we want to find Differentiating u and v w.r.t. x, we get

Question 18
Maharashtra Board Solution
Differentiate e(4x+5) with resepct to 104x.
Solution & Step-by-Step Answer:
Let u = e(4x+5) and v = 104x Then we want to find Differentiating u and v w.r.t. x, we get

Question 19
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Find , if y = log x.
Solution & Step-by-Step Answer:
y = log x Differentiating w.r.t. x, we get Differentiating again w.r.t. x, we get
Question 20
Maharashtra Board Solution
Find , if y = 2at, x = at2.
Solution & Step-by-Step Answer:
x = at2, y = 2at Differentiating x and y w.r.t. t, we get

Question 21
Maharashtra Board Solution
Find , if y = x2. ex
Solution & Step-by-Step Answer:
y = x2. ex Differentiating w.r.t. x, we get = ex (2x + 2 + x2 + 2x) = ex (x2 + 4x + 2).

Question 22
Maharashtra Board Solution
If x2 + 6xy + y2 = 10, then show that .
Solution & Step-by-Step Answer:
x2 + 6xy + y2 = 10 ……..(1) Differentiating both sides w.r.t. a, we get



Question 23
Maharashtra Board Solution
If ax2 + 2hxy + by2 = 0, then show that = 0.
Solution & Step-by-Step Answer:
ax2 + 2hxy + by2 = 0 ……..(1) ∴ ax2 + hxy + hxy + by2 = 0 ∴ x(ax + hy) + y(hx + by) = 0 ∴ x(ax + hy) = -y(hx + by) ∴ …….(2) Differentiating (1) w.r.t. x, we get
