Maharashtra State Board 11th Maths Solutions Chapter 7 Limits Ex 7.2
I. Evaluate the following limits:
Question 1
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Question 2
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Question 3
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Question 4
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Question 5
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II. Evaluate the following limits:
Question 1
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Question 2
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Question 3
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Question 4
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Question 5
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Question 6
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As x → 2, numerator and denominator both tend to zero ∴ x – 2 is a factor of both. To find the other factor for both of them, by synthetic division Consider, Numerator = x3 + 0x2 – 7x + 6 ∴ The limit does not exist


III. Evaluate the following limits:
Question 1
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Solution & Step-by-Step Answer:

Question 2
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Question 3
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Solution & Step-by-Step Answer:
As x → 1, numerator and denominator both tend to zero ∴ x – 1 is a factor of both. To find the factor of numerator and denominator by synthetic division Consider, numerator = x4 + 0x3 – 3x2 + 0x + 2


Question 4
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Question 5
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